Class Review: Let’s Do a Proof!

We’re in FOM, we should be able to do a simple proof, right?!


Okay, so let’s try and prove this:

If n is a positive integer such that \frac {1}{n}   is an integer, then n equals 1.

Well, first of all, the beauty of “if, then statements” is that we can already assume half of this is true right off the bat! For this statement to be true, we’ll assume the hypothesis is true. That is, we’re assuming that n must be a positive integer, and that \frac {1}{n}   is an integer. Now all we have to prove is that n can only equal 1 with all other conditions already true! Easy peasy!

Let’s break this down a little further into cases.

Case 1: n > 1. If n is greater than 1, it fulfills the first part of the hypothesis, as it is positive (greater than one), and that it is a whole number (integer), but when put under a one, this awesome integer becomes a big bad fraction, which does not fulfill the second part of the hypothesis, that \frac {1}{n}   has to be an integer. 1 over any number bigger than 1 is a fraction, which is not an integer. Throw ’em out.

Case 2: 0 < n < 1. Alright. If n is between 0 and 1, \frac {1}{n}  either becomes an integer (like with 1/2), which fulfills the second part of the hypothesis (yay!) or doesn’t (like with 2/5). Either way, these numbers in this range are positive, but not whole numbers, and therefore have to be thrown out because they do not fulfill the first part of the hypothesis! Throw ’em out. 

Case 3: n < 0. This does not fulfill the first part of the hypothesis! n must be positive. Throw ’em out. 

Case 4: n = 1. AH. So 1 is a positive, whole number. Which fulfills the first part of the hypothesis. And when 1 is divided by itself, it becomes 1 (surprise), which is an integer! Therefore, we can keep one!

Through these 4 cases, I’ve hopefully shown all possible outcomes of different integer types to prove that only n works!

Which leads me to ask, did I just explain the proof over again, or did I actually prove this statement right?


One thought on “Class Review: Let’s Do a Proof!

  1. Kate,
    Here, you proved by example, while not formally a proof such tact is extremely beneficial both in logic and in life. For instance: using MECE ( to break down a decision into several possible categories and disproving all the other categories as rationale for choosing one. This is great and used readily to make choices and win arguments. However, how can you assert that something is mathematically true?

    In general, for proving something, assume the hypothesis and use that to derive the conclusion. The proof I wrote for this isn’t as efficient and direct as it should have been. However, see here: for an example of structuring a proof.


Leave a Reply

Fill in your details below or click an icon to log in: Logo

You are commenting using your account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s